NECO Answers 2016: NECO Physics Practical Answers and Questions Posted Here

NECO Answers, NECO Runs, NECO Practicals Answers, NECO Expo, NECO Runz, NECO Answers Today, Free NECO Answers: Here We Post NECO Practical Questions and Answers For Physics – 7th June 2016.

Exam Runs, JAMB runs, NECO Answers, NECO Runs, NECO Practicals Answers, NECO Expo, NECO Runz, NECO Answers Today, Free NECO Answers: Here We Post NECO Practical Questions and Answers

NECO ANSWERS: NECO PHYSICS PRACTICAL ANSWERS FOR MAY/JUNE 2016 EXAMINATION

NECO Practical Questions and Answers For Physics – 7th June 2016.

NECO PHYSICS PRACTICAL ANSWERS
================================

1)
S/N – |1|2|3|4|5|
M(g) – |50.0|100.0|150.0|200.0|250.0|
Lv(cm) – |50.0|50.0|50.0|50.0|50.0|
L1(cm) – |60.0|70.0|80.0|90.0|100.0|
y=Le-v(cm^3) – |10.00|20.00|30.00|40.00|50.00|

(1aviii)
Slope=(250.0-150.0)/(647.10-323.55)
=100.0/323.55
=0.309

1aix)
i. i avoided error due to parallel
ii. i ensured that the mass is gently dropped into the liquid

(1bi)
Archimedes principle states that when a body is wholly or partly immersed in a liquid the weight of the body is equal to the mass of the fluid displaced

1bii)
volume of the wood = 2.0 × 10^-5m^3
mass = 5.0 × 10^-3kg
g = 10.0ms^-2
density of water = 1.0 × 10^3kgm^-3
volume of object = mass/density
density = mass/volume
density of the object = mass of the object/volume
= 5.0×10^-3/2.0×10^-5
= 2.5×10^2kgm^3
upthrust = volume 0f the object × density of liquid × g
=2.0×10^-5 × 1.5×10^2×10
= 0.3N

NECO Physics Practicals Answers

3)
TABULATE READINGS
R(N) – |2.00| |4.00| |6.00| |8.00| |10.00|
1(A) – |2.85| |2.21| |2.00| |1.75| |1.65|
R^-1 – |0.5| |0.25| |0.17| |0.13| |0.10|

PRECAUTIONS
i)i ensured clean terminals
ii)i avioved zero error on the ammeter used
iii)i ensured tight connection of all wires

3b)
ohm’s law states that the current flowing through a metallic conductor is proportional to its portential difference provided that physical condition is constant i.e V x I

(3bii)
E&L
E=kL
E/L=k


E1/L1=E2/L2
l2=E2L1/E1=(1.5 *1)/2.5
L2=0.6cm
the new balance point when 1.5v cell is connected
across it is 0.6cm
3c)
slope(s) = DR^-1/DI = 0.25-0.10/2.21-1.65
=0.15/0.56
slope(s)=0.27
intercept c = -0.35
evaluation
1/5=1/0.27=3.70
evalution
1/C = 1/-0.35
=-2.86

We Post Free NECO Answers Here.

For Faster Answers Kindly Like Our Facebook Page Now And Get Examination Question and Answers for free

Click Like: for Nigeria University News, Polytechnic News, JAMB UTME, Post-UTME, WAEC, NECO, NABTEB, GCE and more Updates on Facebook Page

Tags:

RSSComments (0)

Trackback URL

Leave a Reply