NECO General Mathematics Objective & Theory Answers – 2016

National Examinations Council, NECO Mathematics Answers & Questions for 2016/2017 session.

For candidates writing the 2016/2017 NECO May/June Examination Nationwide, we present the correct and confirmed NECO Mathematics Answers here. Below is the Questions and Answers.

Exam Runs, JAMB runs, NECO Answers, NECO Runs, NECO Practicals Answers, NECO Expo, NECO Runz, NECO Answers Today, Free NECO Answers: Here We Post NECO Practical Questions and Answers

NECO ANSWERS: NECO MATHEMATICS ANSWERS FOR MAY/JUNE 2016 EXAMINATION

NECO Answers For Mathematics Objectives & Theory – 21 June 2016.

=====================

NECO MATHS OBJ :-

1-10: ADADDDCEBE
11-20: CCDCAACECA
21-30: DCDAECAEED
31-40: EAADBEEADC
41-50: BBDCCBCECD
51-60: CADBAECDEC

NECO MATHEMATICS THEORY ANSWERS

(1a)
Tabulate: Draw both vertical and horizontal lines across the digits. I drew only verticals cos it’s txt messaging.

x|1|2|3|4
1|1|2|3|4
2|2|4|0|2
3|3|0|3|0
4|4|2|0|4

(1b)
S.I=PRT
P=N15,000, R=10%, T=3yrs
S.I=#15,000, R=10%, T=3yrss
S.I=15,000* 10/100 *3
S.I=N4,500
A=P+S.I
A=N15,000+N4,500
A=#19,500

============================

3)
Let x represent Donald’s age
and let y represent his son’s age
x=5y—(1)
(x-4(y-4)=448—(11)
substitute for x in (11)
5y^2-20y-4y+16=448
5y^2-24y+16-448=0
5y^2-24y-432=0
y=-b+_sqroot(b^2-4ac)/2a
a=5, b=-24 c=-432
y=24+_sqroot[(-24^2)-4*5*-432]/2*5
y=24+_sqroot(576+8640)/10
y=24+_sqroot(9216)/10
y=24+_96/10
y=24+96/10 or 24-96/10
y=120/10 or -72/10
y=12 or -7.2
since age cannot be negative
y=12years

but x=5y
x=5*12
x=60years

================================

(4a)
Convert 30000 litres to metres
= 30000/1000 metres
= 30metres
Depth of fuel = h * 7.5*4.2 = 30m^3
= 31.5hm^3 = 30m^3
= h = 30m^3/31.5m
= h = 0.9m

(4b)
Depth of the tank = l*b*h
where l= 7.5, b = 4.2, h = 1.2
=(7.5 * 4.2 * 1.2)m^3
=37.8m^3
Convert metres to litres = 37.8*
1000litres
= 37800litres
Litres of fuel needed to fill the tank=37800litres/30800litres
=7800litres

================================

(5a)
sector for building project =48000/144000*360=120degree
sector for education = 32,000/144000*360=80degree
sector for saving = 19200/144000*360=48degree
sector for maintenance = 12000/144000*360=30degree
sector for miscellaneous = 7200/144000*360=18degree
sector for food items = 360-(120+80+48+30+18)
=360-296
=64degree
THEN DRAW A PIE CHART WITH THE ANSWERS YOU GOT ABOVE.

(5b)
Food = 48000 + 32000 + 19200 +
1200 +7200 + x = 144000
Food => 118400 + x = 144000
Food => x = 144000 — 118400
Food = x = #25,600

=================================

(6)
3sqroot[(41.02*sqroot0.7124)/(42.87*0.207*0.0404)]
Tabulate
No|log
41.02|16130
*sqroot0.7124|(1^-.8527)/2
|(2^-+1.8527)/2
|1^-9264
41.02*sqroot0.7124|1.6130
|+1^-.9264
|=1.5394
42.87|1.6322
*0.207|+1^-.3160
|0.9482
*0.0404|+2^-.6064
|=1^-.5546

|1.5394
|1^-.5546
|=(1.9848)/3
antilog4.588|0.6616
Answer=4.588

==================================

(7a)
3^2n+1 – 4(3^n+1)+9=0
3^2-3 – 4(3^n -3)+9=0
(3^n)^2-3 – 4(3^n -3)+9=0
let 3^n = p
p^2 -3 – 4(p-3)+9=0
3p^2/3 – 12p/3 + 9/3 = 0
p^2 – 4p + 3 = 0
p^2 – 3p – p + 3 = 0
p^2p(p-3) – 1(p-3) = 0
(p-1)(p-3) = 0
p-1 = 0 or p-3 = 0
p = 1 or 3
Recall 3^n = p
when p=1
3^n = 3^0
n = 0
when p = 3
3^n = 3^1
n = 1

(7b)
log(x^2+4) = 2+logx – log^20
log(x^2+4) = log^100 = log^x – log^20
(x^2+4) = log(xx)
x^2+4 = 5x
x^2-5x+4 = 0
x^2-4x – x +4 = 0
x(x-4) – 1(x-4) = 0
(x-1)(x-4) = 0
x-1 = 0 or x-4 = 0
x = 1 or 4

==========================

(8ai)
In <> ABC
Cos B=(a^2+c^2-b^2)/2ac
Cos B=(13^3+13^2-10^2)/(2*13*13)
Cos B=(338-100)/338
Cos B=238/338
Cos B=0.7041
B=cos^-0.7041
B=45.2degrees
therefore =90.4degrees
In <>AOC
By sine rule
r/sine44.8=10/sine90.4
r=10sin44.8/sin90.4
r=7.05cm

(8aii)
Circumference =2*pie*R
=2*22/7*7.05
=44.31
=44.3cm(1d.p)

(8b)
p(-1,2) , (2,6)
(y-y1)/(y2-y1)=(x-x1)/(x2-x1)
(y-2)/(6-2)=(x+1)/(2+1)
(y-2)/4=(x+1)/3
3(y-2)=4(x+1)
3y-6=4x+4
3y-4x=10

=============================

(9a)
Let the lens digit x and unit digit be y,
therefore x-y=5 —(1)
3xy-(10x+y)=14 —-(2)
3xy-10x-y=14 —–(3)
frm eq(1); x=5+y — (4)
therefore, 5(5+y)(y)-10(5+y)-y=14
(15+3y)y-50-10y-y=14
3y^2+4y-50-14=0
3y^2+4y-64=0
3y^2 -12y + 16y-64=0
3y(y-4)+16(y-4)=0
(3y+16)(y-4)=0
y=-16/3 or 4
therefore from eqn(1);
x+4=5
x=5+4=9
the number is 94

(9b)
(3-2x)/ 4 + (2x-3)/3
(3(3-2x)+4(2x-3))/12
(9-6x+8x-12)/12
=(2x-3)/12

============================

(10a)
y=(2x^2 + 3)^5
let U=2x^2 + 3
Y=u^5
du/dx = 4x
dy/du = 5u^4
dy/du = (2x^2 + 3)^4
dy/dx = du/dx dy/du
dy/dx = 4x.5(2x^2 + 3)^4
dy/dx = 20x(2x^2 + 3)^4

(10b)
y=3x^2 + 2x +5
dy/dx =6x + 2
dy/dx =6(3) +2
dy/dx =18+2
dy/dx =20

(10c)
R-W=Wv^2/gx
Wv^2=gx(R-W)
Wv^2=gRx-Wgx
Wv^2+Wgx=gRx
W(v^2 + gx) =gRx
W=gRx/V^2 + gx
R=2, g=10, x=3/2, V=3
W= 10*2*3/2/3^2 + 10*3/5
W=30/9+15
W=30/24
W=5/4

(12a)
TABULATE
class interval:50-54,55-59,60-64,65-69,70-74
F:5,5,15,12,3=40
x:52,57,62,67,72
x:260,285,930,804,216=2495
x-x^-:-10.4,-5.4,-0.4,4.6,9.6
(x-x^-)^2:108.16,29.16,0.16,23.16,92.16
F(x-x^-)^2:540.8,145.8,2.4,253.92,276.48=1219.4

(12bi)
Mean(x^-)=Efx/Ef=2495/40
=62.4

(12bii)
Variance=Ef(x-x^-)^2/Ef=1219.4/40
=30.485

(12biii)
Standard deviation=sqroot[Ef(x-x^-)^2/Ef
=Sqroot1219.4/40
=sqroot30.485
=5.52

—————————————–

We Post Free NECO Answers Here But You Will Need To Like Our FB Page.

For Faster Answers Kindly Like Our Facebook Page Now And Get Examination Question and Answers for free.

NOTE: Online Answers comes 1hrs:30mins after the Commencement.

THIS IS HOW ANSWERS WILL COME TO YOUR PHONE, THE INTERPRETATION IS HOW U ARE GONNA WRITE IT ON YOUR PAPER!!!

/ means DIVISION
* means multiplication

degree means °

tita u should know dat ( Θ ).

rais means raise to power
^ means raise to power
sqr rut/ squar rut means square root

—-(1) means equation 1
yr means year
f(x-xbar) means x MINUS x BAR as in statistics which means that MINUS WILL BE ON TOP OF x.

, (Comma) means NEXT LINE, THIS MEANS THAT THE FOLLOWING NUMBER IS UNDER THE NUMBER IT IS FOLLOWING i.e UNDER. It is usually used during STATISTICS when drawing a table.
EXAMPLE 1.

X:1,2,3,4,
FX: 4,6,8,10
FX-Xbar: 10,8,6,4,
DRAW A TABLE WITH X|FX|(FX-Xbar)
The above statement means that:
~For X, it has 1 2 3 4 5 6 under it. which means 1 is under 2, 2 is under 1, 3 is under 2, 4 is under 3 and so on…
~Under FX you have 4, then 6 under 4, then 8 under 6, then 10 under 8, then 12 under 10…..
~Under FX-Xbar you have 10, then 8 under 10, then 6 under 8, then 4 under 6, then 2 under 4, then 1 under 2….

IN A CLEARER WAY:
→ comma means NEXT LINE(e.g)
x : 1,2,3
fx : 4,5,6
fx-xbar : 10,8,6,4

x|fx |fx-x¯¯|
1| 4 | 10 |
2| 6 | 8 |
3| 8 | 6 |
4| 10| 4 |

ANOTHER EXAMPLE:
Class interval: 60-64,65-69,70-74,75-79,80-84,85-89,90-94,95-99.
X: 62,67,72,77,82,87,92,97.
F: 2,3,6,11,8,7,2,1.
FX: 124,201,432,847,656,609,184,97.
F(x-x bar)2: 561.12,414.18,273.36,33.66,84.48,476.42,351.12,333.06

MEANING OF THE ABOVE EXPRESSION:
Bar means Minus on top of d number or Variable and comma means next line which means each of them are unda. Eg 60-64 is unda Class interval, then 65-69 is unda 60-64,etc .So comma means unda.
NOTE THAT WHEN U SEE SOMETHING LIKE THE ABOVE TWO EXAMPLES, U WILL NEED TO DRAW A TABLE..

YOU NEED TO KNOW THESE ALSO:

MATHS CODES:

1) ,(comma) means next line.
(e.g)
x : 1,2,3
fx : 4,5,6
fx-xbar : 7,8,9

x|fx |x¯¯|
1| 4 | 7 |
2| 5 | 8 |
3| 6 | 9 |

2)*=multiplication sign.

3)^ = Riase to pwer

4)P also means raised to power eg 10P6 means 10 raised to power six.

5)log3(base 4) ..Note:the base must be SUBSCRIPT .

6)x bar = mean symbol(x¯¯)

7)Pie = pie symbol eg Area of a circle is (Pie r2).

8)Tita = θ eg Sinθ.

10)Root or Rut or Sqrt or sqr root = √ ; eg Root2 means √2

11)/ means ÷

12)—-(1) means equation 1

Click Like: for Nigeria University News, Polytechnic News, JAMB UTME, Post-UTME, WAEC, NECO, NABTEB, GCE and more Updates on Facebook Page

Tags:

RSSComments (0)

Trackback URL

Leave a Reply